![From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw . From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw .](https://haygot.s3.amazonaws.com/questions/1608485_1740056_ans_85323eb8ce264097bbbec05b4cddfb7e.jpg)
From the dissociation constants Ka and Kb for an acid and its conjugate base, show that Ka· Kb = Kw .
![CALCULATING Ka Kb Kw, ICE Tables, ACID DISSOCIATION CONSTANT Power Points & M.C. WITH ANSWERS (59PGS) | Teaching Resources CALCULATING Ka Kb Kw, ICE Tables, ACID DISSOCIATION CONSTANT Power Points & M.C. WITH ANSWERS (59PGS) | Teaching Resources](https://d1e4pidl3fu268.cloudfront.net/ea0ab3df-3e2f-48b1-bd7f-6960ac591bcc/00.jpg)
CALCULATING Ka Kb Kw, ICE Tables, ACID DISSOCIATION CONSTANT Power Points & M.C. WITH ANSWERS (59PGS) | Teaching Resources
What is value of Ka and kb for water (H20) and how numerically prove that ka ×kb=kw in case of water? - Quora
![SOLVED: Helpful Equations pH = -log [H2O+] Kw = Ka × Kb [ATJ[H2O+1 [HA]] = pOH -log [OH-] 14 = pH + pOH [HA][OH-] [A-] Kb Henderson-Hasselbalch Equation [A-] pH = pKa log - [HA] SOLVED: Helpful Equations pH = -log [H2O+] Kw = Ka × Kb [ATJ[H2O+1 [HA]] = pOH -log [OH-] 14 = pH + pOH [HA][OH-] [A-] Kb Henderson-Hasselbalch Equation [A-] pH = pKa log - [HA]](https://cdn.numerade.com/ask_images/9f4de4f19628424f8aea53cff3ecadcb.jpg)
SOLVED: Helpful Equations pH = -log [H2O+] Kw = Ka × Kb [ATJ[H2O+1 [HA]] = pOH -log [OH-] 14 = pH + pOH [HA][OH-] [A-] Kb Henderson-Hasselbalch Equation [A-] pH = pKa log - [HA]
![NEET UG - Ionic equilibrium 09 Relation between ka, kb and kw and based numerical Offered by Unacademy NEET UG - Ionic equilibrium 09 Relation between ka, kb and kw and based numerical Offered by Unacademy](https://edge.uacdn.net/A9PFQ5CG4GCE14IUYN1J/images/2.jpeg?fm=jpg&w=480)